2021/04/25
遍历链表的过程中,把结点分别收集到两个链表中。
class Solution {
public ListNode partition(ListNode head, int x) {
ListNode less = new ListNode(0);
ListNode greater = new ListNode(0);
ListNode p = less;
ListNode q = greater;
while (head != null) {
ListNode t = head.next;
head.next = null;
if (head.val < x) {
p.next = head;
p = p.next;
} else {
q.next = head;
q = q.next;
}
head = t;
}
p.next = greater.next;
return less.next;
}
}